3(x)=2x^2-5x+1

Solution for 3(x)=2x^2-5x+1 equation:

3(x)=2x^2-5x+1

We move all terms to the left:

3(x)-(2x^2-5x+1)=0

We get rid of parentheses

-2x^2+3x+5x-1=0

We add all the numbers together, and all the variables

-2x^2+8x-1=0

a = -2; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·(-2)·(-1)
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{14}}{2*-2}=\frac{-8-2\sqrt{14}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{14}}{2*-2}=\frac{-8+2\sqrt{14}}{-4}
$